Properties of Square - Difference of Consecutive Numbers


 
 
Concept Explanation
 

Properties of Square - Difference of Consecutive Numbers

Property :

For every natural number n,

                            (n+1)^{2}-n^{2}=(n+1)+n

i.e., the difference of squares of two consecutive natural numbers is equal to their sum

Proof:  For any natural number n, we have

                (n+1)^{2}-n^{2}=(n+1+n)(n+1-n)    [Using: a^{2}-b^{2}=(a+b)(a-b)]

                                         =(n+1+n)

ILLUSTRATION:  9^{2}-8^{2}=9+8=17

                         19^{2}-18^{2}=19+18=37

                        28^{2}-27^{2}=28+27=55

                        136^{2}-135^{2}=136+135=271 etc.

Property:

Between the squares of two consecutive i.e. n² and (n+1), there are 2n non square numbers.

Illustration:  The number of non square numbers that lie between the square of 8 and 9 = 8 X 2 = 16

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Sample Questions
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Question : 1

How many non square numbers lie between 11^2 ;and ;12^2?

Right Option : C
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Question : 2

Find the difference in the squares of 1023 and 1024 .

Right Option : C
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Question : 3

Without actual squaring find the value of (685)^{2}-(684)^{2}.

Right Option : D
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